5.23x-4.9x^2=0

Solution for 5.23x-4.9x^2=0 equation:

5.23x-4.9x^2=0

a = -4.9; b = 5.23; c = 0;
Δ = b2-4ac
Δ = 5.232-4·(-4.9)·0
Δ = 27.3529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.23)-\sqrt{27.3529}}{2*-4.9}=\frac{-5.23-\sqrt{27.3529}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.23)+\sqrt{27.3529}}{2*-4.9}=\frac{-5.23+\sqrt{27.3529}}{-9.8}
$